The current in the arm $CD$ of the circuit will be
A${i_1} + {i_2}$
B${i_2} + {i_3}$
C${i_1} + {i_3}$
D${i_1} - {i_2} + {i_3}$
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B${i_2} + {i_3}$
b (b) According to Kirchhoff's law ${i_{CD}} = {i_2} + {i_3}$
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