The current through a wire depends on time as $i = (2+3t)\, mA$. The charge crossing through a section of the wire in $1\, min$ is .............. $\mathrm{C}$
Medium
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$i=2+3 t$
$\int \mathrm{d} q=\int i d t$
$\mathrm{q}=\int_{0}^{60} 2+3 \mathrm{t} \mathrm{dt}\left(\times 10^{-3}\right)$
$\mathrm{q}=\left[2 \mathrm{t}+\frac{3 \mathrm{t}^{2}}{2}\right]_{0}^{60} \times 10^{-3}$
$=[120+5400] \times 10^{-3}=5.52$ $\mathrm{coulamb}.$
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