MCQ
The de Broglie wavelength $\lambda$ associated with a proton increases by $25 \%$, if its momentum is decreased by $p_0$. The initial momentum was
  • A
    $4 p_0$
  • B
    $\frac{p_0}{4}$
  • $5 p_0$
  • D
    $\frac{p_0}{5}$

Answer

Correct option: C.
$5 p_0$
c
(c)

$\frac{\lambda_2-\lambda_1}{\lambda_1}=\frac{25}{100}$

$\frac{\lambda_2}{\lambda_1}=\frac{5}{4} \Rightarrow \frac{P_1}{P_2}=\frac{5}{4}$

$P_2-P_1=-P_0$

$\frac{4 P_1}{5}-P_1=-P_0$

$P_1=5 P_0$

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