The decreasing order of reactivity of $m-$ nitrobromobenzene $(I), 2, 4, 6-$ trinitrobromo-benzene $(II), p-$ nitrobromobenzene $(III)$, and $2,4-$ dinitrobromobenzene $(IV),$ towards $OH^-$ ions is
A$I > II > III > IV$
B$II > IV > III > I$
C$IV > II > I I I > I$
D$II > IV > I > III$
Medium
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B$II > IV > III > I$
b $(b)$ More $-NO_2$ group more will be reactivity toward $HO^{\ominus}$ ion towards $S_NAr.$
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$(i)$ chlorobenzene is mono-nitrated to $M$
$(ii)$ nitrobenezene is mono-chlorinated to $N$
$(iii)$ anisole is mono-nitrated to $P$
$(iv)\, 2-$ nitrochlorobenzene is mono-nitrated to $Q.$
Out of $M, N, P$ and $Q$ the compound that undergoes reaction with $aq. NaOH$ fastest is
A compound $(x)$ with molar mass $108 \mathrm{~g} \mathrm{~mol}^{-1}$ undergoes acetylation to give product with molar mass $192 \mathrm{~g} \mathrm{~mol}^{-1}$. The number of amino groups in the compound $(\mathrm{x})$ is . . . .. .
$STATEMENT-1$: Aniline on reaction with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at $0^{\circ} \mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate. and
$STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at $0^{\circ} \mathrm{C}$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.