The decreasing order of reactivity of $m-$ nitrobromobenzene $(I), 2, 4, 6-$ trinitrobromo-benzene $(II), p-$ nitrobromobenzene $(III)$, and $2,4-$ dinitrobromobenzene $(IV),$ towards $OH^-$ ions is
  • A$I > II > III > IV$
  • B$II > IV > III > I$
  • C$IV > II > I I I > I$
  • D$II > IV > I > III$
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    $(i)$ chlorobenzene is mono-nitrated to $M$
    $(ii)$ nitrobenezene is mono-chlorinated to $N$
    $(iii)$ anisole is mono-nitrated to $P$
    $(iv)\, 2-$ nitrochlorobenzene is mono-nitrated to $Q.$
    Out of $M, N, P$ and $Q$ the compound that undergoes reaction with $aq. NaOH$ fastest is
    View Solution
  • 2
    Nitrobenzene at room temperature is
    View Solution
  • 3
    Which of following is not correct ?
    View Solution
  • 4
    A compound $(x)$ with molar mass $108 \mathrm{~g} \mathrm{~mol}^{-1}$ undergoes acetylation to give product with molar mass $192 \mathrm{~g} \mathrm{~mol}^{-1}$. The number of amino groups in the compound $(\mathrm{x})$ is  . . . .. .  
    View Solution
  • 5
    Give the product of the following reaction sequence
    View Solution
  • 6
    Which does not give isocyanide test ?
    View Solution
  • 7
    $R$ is
    View Solution
  • 8
    The main product of following reaction will be

    (image) $\to $  Product

    View Solution
  • 9
    In the given reaction $[X]$ is
    View Solution
  • 10
    $STATEMENT-1$: Aniline on reaction with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at $0^{\circ} \mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate. and

    $STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at $0^{\circ} \mathrm{C}$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.

    View Solution