The circuit shown here is used to compare the $e.m.f.$ of two cells ${E_1}$ and ${E_2}({E_1} > {E_2})$. The null point is at $C$ when the galvanometer is connected to ${E_1}$. When the galvanometer is connected to ${E_2}$, the null point will be
  • ATo the left of $C$
  • BTo the right of $C$
  • CAt $C$ itself
  • DNowhere on $AB$
Easy
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