d
$P_{R}=0.5 W$
$\Rightarrow i ^{2} R =0.5 W$
$Also , V = E - ir$
$2.5=3-$ ir
$\Rightarrow$ ir $=0.5$
Power dissipated across 'r' : $P_{r}=i 2 r$
$Now$ iR $=2.5$
ir $=0.5$
On dividing : $\frac{ R }{ r }=5$
$\operatorname{Now} \frac{ P _{ R }}{ P _{ r }}=\frac{ i ^{2} R }{ i ^{2} r } \Rightarrow \frac{ P _{ R }}{ P _{ r }}=\frac{ R }{ r } \Rightarrow \frac{ P _{ R }}{ P _{ r }}=5$
$\Rightarrow P _{ r }=\frac{ P _{ R }}{5}$
$\Rightarrow P _{ r }=\frac{0.50}{5} \Rightarrow P _{ r }=0.10 W$
