MCQ
The degree of hydrolysis of $0.1\ M$ solution of $ArNH_3^+ Cl^-$ is $0.01$ . Find the degree of hydrolysis in $0.4\ M$ solution of $ArNH_3^+ Cl^-$
- A$0.1$
- B$0.01$
- ✓$0.005$
- D$0.05$
✓
Answer
Correct option: C.
$0.005$
c
$\alpha_{1}=\sqrt{\frac{k_{\mathrm{w}}}{\mathrm{k}_{\mathrm{b}} \cdot C_{1}}} \quad \frac{\alpha_{1}}{\alpha_{2}}=\frac{\sqrt{\mathrm{C}_{2}}}{\sqrt{\mathrm{C}_{1}}}$
$\alpha_{1}=\sqrt{\frac{k_{\mathrm{w}}}{\mathrm{k}_{\mathrm{b}} \cdot C_{1}}} \quad \frac{\alpha_{1}}{\alpha_{2}}=\frac{\sqrt{\mathrm{C}_{2}}}{\sqrt{\mathrm{C}_{1}}}$
$\alpha_{2}=\sqrt{\frac{\mathrm{k}_{\mathrm{w}}}{\mathrm{k}_{\mathrm{b}} \cdot \mathrm{C}_{2}}} \quad \frac{0.01}{\alpha_{2}}=\sqrt{\left(\frac{0.4}{0.1}\right)}=2$
$\alpha_{2}=\frac{0.01}{2}=0.005$
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