MCQ
The $\Delta H_f^o$ for $C{O_2}(g),\,CO(g)$ and ${H_2}O(g)$ are $-393.5, -110.5$ and $-241.8\,kJ\,mol^{-1}$ respectively. The standard enthalpy change (in $kJ$) for the reaction $C{O_2}(g) + {H_2}(g) \to $ $CO(g) + {H_2}O(g)$ is
  • A
    $524.1$
  • $41.2$
  • C
    $-262.5$
  • D
    $-41.2$

Answer

Correct option: B.
$41.2$
(b)$C + {O_2} \to C{O_{2(g)}},\,\,\,\Delta H_f^o = - 393.5\,kJ\,mo{l^{ - 1}}$….$(i)$
$C + \frac{1}{2}{O_2} \to C{O_{(g)}},\,\,\,\Delta H_f^o = - 110.5\,kJ\,mo{l^{ - 1}}$….$(ii)$
${H_2} + \frac{1}{2}{O_2} \to {H_2}{O_{(g)}},\,\,\,\Delta H_f^o$$ = - 241.8\,kJ\,mo{l^{ - 1}}$...$(iii)$
By $(ii) + (iii) -(i)$
$C{O_{2(g)}} + {H_{2(g)}} \to C{O_{(g)}} + {H_2}{O_{(g)}},\,\,\,\Delta H = + 41.2$.

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