Question
The diagram shows three capacitors with their capacitances and with breakdown voltages. What should be the maximum value of external $emf$ of source such that no capacitor breaks down

Answer

In series v $\propto \frac{1}{c}$

${v_1}:{{\rm{v}}_2}:{{\rm{v}}_3}{\rm{ }} = 1:\frac{1}{2}:\frac{1}{3}$

$=6: 3: 2$

for protection of $2\, \mu \mathrm{F}$ having smallest break down voltage

$1=\frac{3}{11} \times \mathrm{E} \Rightarrow \frac{11}{3}$

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