The diameter of a cylinder is measured using a vernier callipers … - Vidyadip

MCQ

The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $5.10 \ cm$ and $5.15 \ cm$ of the main scale. The vernier scale has $50$ division equivalent to $2.45 \ cm$. The $24^{\text {th }}$ division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is :

A
$5.112 \ cm$
✓
$5.124 \ cm$
C
$5.136 \ cm$
D
$5.148 \ cm$

✓

Answer

Correct option: B.

$5.124 \ cm$

b
$50 VSD =2.45 \ cm $

$1 VSD =\frac{2.45}{50} cm =0.049 \ cm $

$\text { Least count of vernier }=1 MSD -1 VSD $

$=0.05 cm -0.049 \ cm $

$=0.001 \ cm $

$\text { Thickness of the object }=\text { Main scale reading }+ \text { vernier scale reading } \times \text { least count } $

$=5.10+(24)(0.001) $

$=5.124 \ cm .$

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