MCQ
The difference between heats of reaction at constant pressure and at constant volume for the reaction $2{C_6}{H_6}(l) + 15{O_2}(g) \to 12C{O_2}(g) + 6{H_2}O(l)$ at ${25\,^o}C$ in $kJ $ is
- ✓$-7.43$
- B$+3.72$
- C$-3.72$
- D$+7.43$
✓
Answer
Correct option: A.
$-7.43$
(a)$\Delta H - \Delta E = \Delta nRT$$ = 3 \times 8.314\,\, \times 298$
$ = - 7432\,\,J = - 7.43\,kJ.$
$ = - 7432\,\,J = - 7.43\,kJ.$
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