MCQ
The difference between the reaction enthalpy change $\left( {{\Delta _r}H} \right)$ and reaction internal energy change $\left( {{\Delta _r}U} \right)$ for the reaction
$2C_6H_6 (l) + 15O_2 (g) \longrightarrow 12CO_2 (g) + 6H_2O(l)$
at $300\, K$ is ....$J\,mol^{-1}$ ($R = 8.314\, J\, mol^{-1}\, K^{-1}$)
- A$0$
- B$2490$
- C$-2490$
- ✓$-7482$
