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Gravitation — Physics STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 SciencePhysicsGravitation1 Mark
MCQ
The difference in the acceleration due togravity at the pole and equator is $(g=$ acceleration due to gravity, $R=$ radius of earth, $\theta=$ latitude, $\omega=$ angular velocity, $\cos 0^{\circ}=1, \cos 90^{\circ}=0 )$
  • A
    $\frac{R \omega^2}{g^2}$
  • B
    $\omega \cos ^2 \theta$
  • ✓
    $R \omega^2$
  • D
    $R \omega^2 \cos ^2 \theta$
✓

Answer

Correct option: C.
$R \omega^2$
$ g_p-g_e=g_0-g_0+R \omega^2$
$g_p-g_e=R \omega^2 $

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