The dimensional formula for young's modulus is
  • A$M{L^{ - 1}}{T^{ - 2}}$
  • B${M^0}L{T^{ - 2}}$
  • C$ML{T^{ - 2}}$
  • D$M{L^2}{T^{ - 2}}$
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    If $V$ denotes the potential difference across the plates of a capacitor of capacitance $C$, the dimensions of $C{V^2}$are
    View Solution
  • 2
    The dimensions of surface tension are
    View Solution
  • 3
    The period of oscillation of a simple pendulum in the experiment is recorded as $2.63\, s, 2.56 s, 2.42\, s, 2.71\, s$ and $2.80 \,s$ respectively. The average absolute error is ......... $s$
    View Solution
  • 4
    The dimensions $\left[ MLT ^{-2} A ^{-2}\right]$ belong to the :
    View Solution
  • 5
    $1kWh = $
    View Solution
  • 6
    In an experiment the angles are required to be measured using an instrument, $29$ divisions of the main scale exactly coincide with the $30$ divisions of the vernier scale. If the smallest division of the main scale is half- a degree $(= 0.5^o  )$, then the least count of the instrument is
    View Solution
  • 7
    Match List$-I$ with List$-II$

    List$-I$ List$-II$
    $(a)$ $h$ (Planck's constant) $(i)$ $\left[ M L T ^{-1}\right]$
    $(b)$ $E$ (kinetic energy) $(ii)$ $\left[ M L ^{2} T ^{-1}\right]$
    $(c)$ $V$ (electric potential) $(iii)$ $\left[ M L ^{2} T ^{-2}\right]$
    $(d)$ $P$ (linear momentum) $( iv )\left[ M L ^{2} I ^{-1} T ^{-3}\right]$

    Choose the correct answer from the options given below

    View Solution
  • 8
    The least count of the main scale of a screw gauge is $1\, mm$. The minimum number of divisions on its circular scale required to measure $5\,\mu m$ diameter of a wire is
    View Solution
  • 9
    The magnitude of any physical quantity
    View Solution
  • 10
    Turpentine oil is flowing through a tube of length $l$ and radius $r$. The pressure difference between the two ends of the tube is $P .$ The viscosity of oil is given by $\eta=\frac{P\left(r^{2}-x^{2}\right)}{4 v l}$ where $v$ is the velocity of oil at a distance $x$ from the axis of the tube. The dimensions of $\eta$ are
    View Solution