MCQ
The dimensional formula of farad is
- A$\left[ {{M^{ - 1}}{L^{ - 2}}TQ} \right]$
- ✓$\left[ {{M^{ - 1}}{L^{ - 2}}{T^2}{Q^2}} \right]$
- C$\left[ {{M^{ - 1}}{L^{ - 2}}T{Q^2}} \right]$
- D$\left[ {{M^{ - 1}}{L^{ - 2}}{T^2}Q} \right]$
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$ x = 2 \sin \omega t \,;$ $ y = 2 \sin \left( {\omega t + \frac{\pi }{4}} \right)$
The path of the particle will be :