A current $i$ flows in a circular coil of radius $r$. If the coil is placed in a uniform magnetic field $B$ with its plane parallel to the field, magnitude of the torque that acts on the coil is
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(c) As shown in the following figure, the given situation is similar to a bar magnet placed in a uniform magnetic field perpendicularly. Hence torque on it
$\tau = MB\sin 90^\circ = (i\pi {r^2})B$
$\tau = MB\sin 90^\circ = (i\pi {r^2})B$
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