Question
The dimensions of a rectangular box are in the ratio of $2: 3: 4$ and the difference between the cost of covering it with sheet of paper at the rates of Rs. 8 and Rs. 9.50 per $m ^2$ is Rs. 1,248 . Find the dimensions of the box.

Answer


Ratio in the dimensions of a box $=2: 3: 4$
Difference in total cost $=$ Rs. 1,248
Difference in rates $=$ Rs. $9.50-$ Rs. $8=$ Rs. 1.50
Let length $(l)=2 x$
Then breadth (b) $=3 x$
And, height $(h)=4 x$
$\therefore$ Surface area $=2( l \times b + b \times h + h \times l )$
$=2(2 x \times 3 x +3 x \times 4 x +4 x \times 2 x )$
$=2\left(6 x^2+12 x^2+8 x^2\right)=2 \times 26 x^2=52 x^2$
First rate of paper $=$ Rs. 9.50 per $m ^2$
And, second rate $=8.00$ per $m ^2$
$\therefore$ First cost $=$ Rs. $52 x^2 \times 9.50$
And, second cost $=$ Rs. $52 x^2 \times 8$
$\therefore 52 x^2 \times 9.50-52 x^2 \times 8=1248$
$\Rightarrow 52 x^2(9.50-8)=1248$
$\Rightarrow 52 x^2(1.50)=1248$
$\Rightarrow x^2=\frac{1248}{52 \times 1.50}=\frac{1248 \times 100}{52 \times 150}=16$
$\Rightarrow x=\sqrt{16}=4$
$\therefore \text { Length }=2 x=2 \times 4=8 m$
$\text { Breadth }=3 x=3 \times 4=12 m$
$\text { Height }=4 x=4 \times 4=16 m$

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