MCQ
The dimensions of power are
  • ${M^1}{L^2}{T^{ - 3}}$
  • B
    ${M^2}{L^1}{T^{ - 2}}$
  • C
    ${M^1}{L^2}{T^{ - 1}}$
  • D
    ${M^1}{L^1}{T^{ - 2}}$

Answer

Correct option: A.
${M^1}{L^2}{T^{ - 3}}$
a
(a) Power = $\frac{{{\rm{Work done}}}}{{{\rm{Time}}}} $$= \left[ {\frac{{M{L^2}{T^{ - 2}}}}{T}} \right] = [M{L^2}{T^{ - 3}}]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The length of second's hand in watch is $1 \,cm.$ The change in velocity of its tip in $15$ seconds is
A monkey of mass $20\,kg$ is holding a vertical rope. The rope will not break when a mass of $25\, kg$ is suspended from it but will break if the mass exceeds $25 \,kg$. What is the maximum acceleration with which the monkey can climb up along the rope ............ $m/{s^2}$ $(g = 10\,m/{s^2})$
It is possible to recognise a person by hearing his voice even if he is hidden behind a wall. This is due to the fact that his voice
In a harmonium the intermediate notes between a note and its octave form
In solids, inter-atomic forces are:
The acceleration of a train between two stations is shown in the figure. The maximum speed of the train is $............\,m/s$
An object is moving with variable speed, then
A motor cycle starts from rest and accelerates along a straight path at $2 \;m / s ^{2}$. At the starting point of the motor cycle there is a stationary electric siren. How far has the motor cycle gone when the driver hears the frequency of the siren at $94 \%$ of its value when the motor cycle was at rest?

(Speed of sound $=330 ms ^{-1}$)

A $20$ $cm$ long capillary tube is dipped in water. The water rises up to $8$ $cm$. If entire arrangement is put in a freely falling elevater the length of water coloumn in the capillary will be ....... $cm$
A body moves on a frictionless plane starting from rest. If $\mathrm{S}_{\mathrm{n}}$ is distance moved between $\mathrm{t}=\mathrm{n}-1$ and $\mathrm{t}$ $=\mathrm{n}$ and $\mathrm{S}_{\mathrm{n}-1}$ is distance moved between $\mathrm{t}=\mathrm{n}-2$ and $t=n-1$, then the ratio $\frac{S_{n-1}}{S_n}$ is $\left(1-\frac{2}{x}\right)$ for $n$ $=10$. The value of $x$ is