The distance between plates of a parallel plate capacitor is $5d$. Let the positively charged plate is at $ x=0$ and negatively charged plate is at $x=5d$. Two slabs one of conductor and other of a dielectric of equal thickness $d$ are inserted between the plates as shown in figure. Potential versus distance graph will look like :
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Voltage would be highest at $x=0 .$ And $E=$ constant $\Rightarrow \propto v \times$ so it would decrease linearly, from $x=0$ to $x$ $-d,$ will remain constant from $x=d$ to $x=2 d$
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