MCQ
The distance between points P ( -1 , 1 ) and Q(5, -7 ) is ------------..
- A11 cm
- B10 cm
- C5 cm
- D7 cm
Let $P\left(x_1, y_1\right)=P(-1,1)$ and $Q\left(x_2, y_2\right)=Q(5,-7)$
Here, $x_1=-1, y_1=1, x_2=5, y_2=-7$
By distance formula,
$d(P, Q)=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$\therefore d(P, Q)=\sqrt{[5-(-1)]^2+(-7-1)^2}$
$\therefore d(P, Q)=\sqrt{36+64}$
$\therefore d(P, Q)=\sqrt{100}$
$\therefore d(P, Q)=10 \mathrm{~cm}$
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