MCQ
The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is $1.1\ Å$.  Given, mass of carbon atom is $12\ a.m.u.$ and mass of oxygen atom is $16\ a.m.u.$, calculate the position of the center of mass of the carbon monoxide molecule
  • A
    $6.3\ Å$ from the carbon atom
  • B
    $1\ Å$ from the oxygen atom
  • $0.63\ Å$ from the carbon atom
  • D
    $0.12\ Å $ from the oxygen atom

Answer

Correct option: C.
$0.63\ Å$ from the carbon atom
c
Let carbon atom is at the origin and the oxygen atom is placed at $x$ - axis ${m_1} = 12$, ${m_2} = 16$, $\vec r_1 = 0\hat i + 0\hat j\,{\rm{and}}\,\, \vec r_2 = 1.1\hat i + 0\hat j$

$\mathop r\limits^ \to   = \frac{{{m_1}\mathop {{r_1}}\limits^ \to   + {m_2}\mathop {{r_2}}\limits^ \to  }}{{{m_1} + {m_2}}}$ $ = \frac{{16 \times 1.1}}{{28}}\hat i$  

$\mathop r\limits^ \to   = 0.63\,\hat i$ i.e. $0.63\ Å$ from carbon atom

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