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STD 11 - 9. straight line — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSTD 11 - 9. straight line1 Mark
MCQ
The distance between the lines $3x - 2y = 1$and $6x + 9 = 4y$ is
  • A
    $\frac{1}{{\sqrt {52} }}$
  • ✓
    $\frac{{11}}{{\sqrt {52} }}$
  • C
    $\frac{4}{{\sqrt {13} }}$
  • D
    $\frac{6}{{\sqrt {13} }}$
✓

Answer

Correct option: B.
$\frac{{11}}{{\sqrt {52} }}$
b
(b)$\therefore $ Distance between two lines = $d = \left| {\frac{{1 + \frac{9}{2}}}{{\sqrt {13} }}} \right|$
$ \Rightarrow $$d = \frac{{11}}{{2\sqrt {13} }} = \frac{{11}}{{\sqrt {52} }}$.

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