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Waves and Sound — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsWaves and Sound1 Mark
MCQ
The distance between the nearest node and antinode in a stationary wave is
  • A
    $\lambda$
  • B
    $\frac{\lambda}{2}$
  • ✓
    $\frac{\lambda}{4}$
  • D
    $2 \lambda$
✓

Answer

Correct option: C.
$\frac{\lambda}{4}$

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