MCQ
The distance between the plates of a parallel plate condenser is $\,4mm$ and potential difference is $60\;volts$. If the distance between the plates is increased to $12\,mm$, then
  • The potential difference of the condenser will become $180\;volts$
  • B
    The $P.D.$ will become $20\;volts$
  • C
    The $P.D.$ will remain unchanged
  • D
    The charge on condenser will reduce to one third

Answer

Correct option: A.
The potential difference of the condenser will become $180\;volts$
a
(a) For capacitor $\frac{{{V_1}}}{{{V_2}}} = \frac{{{d_1}}}{{{d_2}}}$ $==>$ ${V_2} = \frac{{{V_1} \times {d_2}}}{{{d_1}}} = \frac{{60 \times 12}}{4} = 180\,V$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A scooter accelerates from rest for time $t_{1}$ at constant rate $a _{1}$ and then retards at constant rate $a _{2}$ for time $t _{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be ..... .
The time period of a satellite of earth is $5\, hours$. If the separation between the centre of earth and the satellite is increased to $4\, times$ the previous value, the new time period will become ....... $h$
A body of mass $0.5\, kg$ travels on straight line path with velocity $v =\left(3 x ^{2}+4\right) m / s$. The net workdone by the force during its displacement from $x =0$ to $x =2\, m$ is$.......J$
The current in series $LCR$ circuit will be maximum when $\omega$ is
The work function of a photoelectric material is $3.3 eV$. The threshold frequency will be equal to
Calculate radiation power for sphere whose temperature is $227^{\circ} C$ and radius $2\, m$ and emissivity $0.8$ (in $W$)
A microwave of wavelength $2.0 \mathrm{~cm}$ falls normally on a slit of w1dth $4.0 \mathrm{~cm}$. The angular spread of the central maxima of the diffraction pattern obtained on a screen $1.5 \mathrm{~m}$ away from the slit, will be:
A simple pendulum of length $1\, m$ is oscillating with an angular frequency $10\, rad/s$. The support of the pendulum starts oscillating up and down with a small angular frequency of $1\, rad/s$ and an amplitude of $10^{-2}\, m$. The relative change in the angular frequency of the pendulum is best given by
A particle moves with a constant velocity in $X-Y$ plane. Its possible angular momentum w.r.t. origin is
The phase of a particle executing simple harmonic motion is $\frac{\pi }{2}$ when it has