MCQ
The distance between the points $(3, -2)$ and $(-3, 2)$ is:
- A$40$
- B$4 \sqrt{10}$
- C$2 \sqrt{10}$
- ✓$\sqrt{52}$
✓
Answer
Correct option: D.
$\sqrt{52}$
Let us take $(3,-2)$ and $(-3,2)$ as $\left( x _1, y _1\right)$ and $\left( x _2, y _2\right)$
Using distance formjula, $d =\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$d=\sqrt{(-3-3)^2+(2-(-2))^2}$
$d=\sqrt{(-6)^2+(2+2)^2}$
$d=\sqrt{36+(4)^2}$
$d=\sqrt{36+16}$
$d=\sqrt{52}$
Using distance formjula, $d =\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$d=\sqrt{(-3-3)^2+(2-(-2))^2}$
$d=\sqrt{(-6)^2+(2+2)^2}$
$d=\sqrt{36+(4)^2}$
$d=\sqrt{36+16}$
$d=\sqrt{52}$
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