MCQ
The domain of $\sin ^{-1}\left(\frac{2 x+1}{3}\right)$ is
  • A
    $(-2,1)$
  • $[-2,1]$
  • C
    R
  • D
    $[-1,1]$

Answer

Correct option: B.
$[-2,1]$
(B) $\sin ^{-1}\left(\frac{2 x+1}{3}\right)$ is defined for
$-1 \leq \frac{2 x+1}{3} \leq 1$
$\begin{array}{l}\Rightarrow-3 \leq 2 x+1 \leq 3 \Rightarrow-4 \leq 2 x \leq 2 \\ \Rightarrow-2 \leq x \leq 1\end{array}$

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