Download App

Functions — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsFunctions2 Marks
MCQ
The domain of the function
$f(x)=\sqrt{x^2-5 x+6}+\sqrt{2 x+8-x^2}$, is
  • A
    [2,3]
  • B
    [-2,4]
  • ✓
    $[-2,2] \cup[3,4]$
  • D
    $[-2,1] \cup[2,4]$
✓

Answer

Correct option: C.
$[-2,2] \cup[3,4]$
(C)
$f (x)$ is defined, if
$x^2-5 x+6 \geq 0$ and $2 x+8-x^2 \geq 0$
$\Rightarrow(x-2)(x-3) \geq 0$ and $(x-4)(x+2) \leq 0$
$\therefore \quad x \in(-\infty, 2] \cup[3, \infty)$ and $x \in[-2,4]$
$\therefore \quad x \in[-2,2] \cup[3,4]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Functions→Functions — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

$\frac{\sin 3 x-\sin x}{\cos 2 x}=$
→
If $f (x)=\left\{\begin{array}{ll}2 x+1, & x \leq 1 \\ 3- k x^2, & x>1\end{array}\right.$ is continuous at $x=1$, then the value of k is
→
$(1+i)^{10}$, where $i^2=-1$, is equal to
→
$\lim _{x \rightarrow 2} \frac{x^{100}-2^{100}}{x^{77}-2^{77}}$ is equal to
→
$\sin 4 \theta$ can be written as
→
Eccentricity of hyperbola $\frac{x^2}{ k }+\frac{y^2}{ k ^2}=1( k <0)$ is
→
$\lim _{x \rightarrow 1} \frac{1+\cos \pi x}{\tan ^2 \pi x}$ is equal to
→
If the distance of any point P from the points A(a + b, a - b) and B(a - b, a + b) are equal, then the locus of P is
→
If the function $f(x)$ defined by$f(x)= \begin{cases}x \sin \frac{1}{x} & \text { for } x \neq 0 \\ k & \text { for } x \neq 0\end{cases}$ is continuous at $x=0$, then $k=$
→
If $a \tan \theta= b$, then $a \cos 2 \theta+ b \sin 2 \theta=$
→