$f _{2}=\left(\frac{330+ v _{0}}{330}\right)\left(\frac{330}{330- v _{ B }}\right) 420$
$490=\left(\frac{330+ v _{ B }}{330- v _{ B }}\right) 420$
$\frac{7}{6}=\frac{330+ v _{ B }}{330- v _{ B }}$
$v _{ B }=\frac{330}{13} m / s$
$=\frac{330}{13} \times \frac{18}{5} \approx 91 km / hr$

