A taut string at both ends vibrates in its $n^{th}$ overtone. The distance between adjacent Node and Antinode is found to be $'d'$. If the length of the string is $L,$ then
  • A$L = 2d (n + 1)$
  • B$L = d (n + 1)$
  • C$L = 2dn$
  • D$L = 2d (n - 1)$
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