MCQ
The eccentricity of the conic ${x^2} - 4{y^2} = 1$, is
- A$\frac{2}{{\sqrt 3 }}$
- B$\frac{{\sqrt 3 }}{2}$
- C$\frac{2}{{\sqrt 5 }}$
- ✓$\frac{{\sqrt 5 }}{2}$
$\therefore {b^2} = {a^2}({e^2} - 1)$
$⇒$ $\frac{1}{4} + 1 = {e^2}$
$⇒$ $e = \frac{{\sqrt 5 }}{2}$.
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Statement $-1$ : Equation of other roots is $x^2 + cx + ab = 0$
Statement $-2$ : $a + b + c = 0$