The eccentricity of the hyperbola 2 x^2 - y^2 = 6 is - Vidyadip

MCQ

The eccentricity of the hyperbola $2{x^2} - {y^2} = 6$ is

A
$\sqrt 2 $
B
$2$
C
$3$
✓
$\sqrt 3 $

✓

Answer

Correct option: D.

$\sqrt 3 $

d
(d) $\frac{{{x^2}}}{{(6/2)}} - \frac{{{y^2}}}{6} = 1$

==> ${a^2} = 3$ and ${b^2} = 6$

Therefore $e = \sqrt {\frac{{{b^2}}}{{{a^2}}} + 1} $

==> $e = \sqrt 3 $.

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