MCQ
The electric field in an electromagnetic wave is given by ${E}=\left(50\, {NC}^{-1}\right) \sin \omega({t}-{x} / {c})$

The energy contained in a cylinder of volume ${V}$ is $5.5 \times 10^{-12} \, {J}$. The value of ${V}$ is $......{cm}^{3}$ $\left(\right.$ given $\left.\in_{0}=8.8 \times 10^{-12} \,{C}^{2} {N}^{-1} {m}^{-2}\right)$

  • A
    $5000$
  • B
    $1500$
  • $500$
  • D
    $100$

Answer

Correct option: C.
$500$
c
${E}=50 \sin \left(\omega {t}-\frac{\omega}{{c}} \cdot {x}\right)$

Energy density $=\frac{1}{2} \in_{0} {E}_{0}^{2}$

Energy for volume ${V}=\frac{1}{2} \in_{0} {E}_{0}^{2} \cdot {V}=5.5 \times 10^{-12}$

$\frac{1}{2} 8.8 \times 10^{-12} \times 2500 {V}=5.5 \times 10^{-12}$

${V}=\frac{5.5 \times 2}{2500 \times 8.8}=.0005\, {m}^{3}$

$=.0005 \times 10^{6}\,({c} . {m})^{3}$

$=500({c} \, \cdot {m})^{3}$

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