The electric field intensity produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is $E$. The electric field intensity produced by the radiation coming from $60\, W$ at the same distance is $\sqrt{\frac{x}{5}} E$. Where the value of $x=......... .$
JEE MAIN 2021, Diffcult
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$c \in_{0} E ^{2}=\frac{100}{4 \pi \times 3^{2}}$
$c \epsilon_{0}\left(\sqrt{\frac{ x }{5}} E \right)^{2}=\frac{60}{4 \pi \times 3^{2}}$
$\Rightarrow \frac{ x }{5}=\frac{3}{5}$
$\Rightarrow x =3$
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