Download App

2. Electric potential and capacitance — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics2. Electric potential and capacitance1 Mark
MCQ
The electric field $\vec E$ between two points is constant in both magnitude and direction. Consider a path of length d at an angle $\theta = 60^o$ with respect to field lines shown in figure. The potential difference between points $1$ and $2$ is
  • A
    $\frac {E}{d\,cos\,60^o}$
  • ✓
    $Ed\,cos\,60^o$
  • C
    $\frac {Ed}{cos\,60^o}$
  • D
    $\frac {E}{d}\,cos\,60^o$
✓

Answer

Correct option: B.
$Ed\,cos\,60^o$
b
Points $2$ and $3$ are equipotential points. Hence, potential difference between points $1$ and $2$ is the same as that between $1$ and $3$.

                  $\therefore V = Ed \,cos \,60^o$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 2. Electric potential and capacitance→2. Electric potential and capacitance — all question types→Physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

An electromagnetic wave in vacuum has the electric and magnetic field $\vec E$ and $\vec B$ , which are always perpendicular to each other. The direction of polarization is given by $\vec X$ and that of wave propagation by $\vec k$ . Then
→
The figure shows a schematic diagram showing the arrangement of Young's Double Slit Experiment Identify the correct statement $(s)$ if the source slit $S$ moved closer to $S_1S_2$, i.e. the distance $\lambda$ decreases
→
The toroid of radius $10 \ cm$ has $100$ turns. If a current of $0.1$ ampere is flowing in it, then the value of the magnetic field on the axis of the toroid will be:
→
Two identical circular wires of radius $20\,cm$ and carrying current $\sqrt{2}\,A$ are placed in perpendicular planes as shown in figure. The net magnetic field at the centre of the circular wire is $.............\times 10^{-8}\,T$. (Take $\pi=3.14$ )
→
An electron is projected normally from the surface of a sphere with speed $v_0$ in a uniform magnetic field perpendicular to the plane of the paper such that its strikes symmetrically opposite on the sphere with respect to the $x-$ axis. Radius of the sphere is $'a'$ and the distance of its centre from the wall is $'b'$ . What should be magnetic field such that the charge particle just escapes the wall
→
Conductivity of a photodiode starts changing only if the wavelength of incident light is less than $660 \mathrm{~nm}$. The band gap of photodiode is found to be $\left(\frac{x}{8}\right) \mathrm{eV}$. The value of $x$ is :

(Given, $\mathrm{h}=6.6 \times 10^{-34} \mathrm{Js}, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ )

→
In the circuit shown, $A$ and $V$ are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be ............... $V$
→
A short magnet of moment $6.75\, Am^2$ produces a neutral point on its axis. If horizontal component of earth's magnetic field is $5 \times {10^{ - 5}}\,Wb/{m^2}$, then the distance of the neutral point should be.....$cm$
→
Potential atapoint $A$ is $3 $ $ volt$ and atapoint $B$ is $7$ $volt$,an electron is moving towards $A$ from $B.$
→
$_6^{12}C$ absorbs an energetic neutron and emits beta particles. The resulting nucleus is
→