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Capacitance of a capacitor made by a thin metal foil is $2\,\mu F$. If the foil is folded with paper of thickness $0.15\,mm$, dielectric constant of paper is $2.5$ and width of paper is $400\,mm$, then length of foil will be.....$m$
The distance between two plates of a capacitor is $d$ and its capacitance is $C _1$, when air is the medium between the plates. If a metal sheet of thickness $\frac{2 d }{3}$ and of same area as plate is introduced between the plates, the capacitance of the capacitor becomes $C _2$. The ratio $\frac{ C _2}{ C _1}$ is:
Four identical plates $1, 2, 3$ and $4$ are placed parallel to each other at equal distance as shown in the figure. Plates $1$ and $4$ are joined together and the space between $2$ and $3$ is filled with a dielectric of dielectric constant $k$ $=$ $2$. The capacitance of the system between $1$ and $3$ $\&$ $2$ and $4$ are $C_1$ and $C_2$ respectively. The ratio $\frac{{{C_1}}}{{{C_2}}}$ is
A capacitor of capacitance $1$ $\mu F$ withstands the maximum voltage $6$ $kV$ while a capacitor of $2$ $\mu F$ withstands the maximum voltage $4$ $kV$. What maximum voltage will the system of these two capacitor withstands if they are connected in series?......$kV$