The electromotive force for the cell is C u_ ( s ) |Cu_ ( 0.004 ,… - Vidyadip

MCQ

The electromotive force for the cell is $C{u_{\left( s \right)}}|Cu_{\left( {0.004\,M} \right)}^{ + 2}||Cu_{\left( {0.1\,M} \right)}^{ + 2}|C{u_{\left( s \right)}}$

A
$ - \frac{{RT}}{F}\,\ln \left( {0.02} \right)$
B
$ + \frac{{RT}}{F}\,\ln \left( {0.04} \right)$
C
$ + \frac{{RT}}{F}\,\ln \left( {0.2} \right)$
✓
$ - \frac{{RT}}{F}\,\ln \left( {0.2} \right)$

✓

Answer

Correct option: D.

$ - \frac{{RT}}{F}\,\ln \left( {0.2} \right)$

d
${E}_{\text {cell }}={E}_{\text {cell }}^{o}-\frac{\mathrm{RT}}{\mathrm{nF}} \ln \frac{\left[\mathrm{Cu}^{+2}\right]_{\text {anode }}}{\left[\mathrm{Cu}^{+2}\right]_{\text {cathode }}}$

in concentration cell

$ {E}_{\text {cell }}^{o} =0$

$\therefore $ ${E}_{\text {cell }}=-\frac{\mathrm{RT}}{2 \mathrm{F}}\, \ln \,\frac{0.004}{0.1} $

$=\,-\,\frac{\mathrm{RT}}{2 \mathrm{F}} \ln (0.2)^{2}$

$\mathrm{E}_{\text {cell }} =-\frac{\mathrm{RT}}{\mathrm{F}} \ln (0.2)$

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