MCQ
The electronic configuration for Neodymium is: [Atomic Number for Neodymium $60$]
- ✓$[\mathrm{Xe}] 4 \mathrm{f}^4 6 \mathrm{~s}^2$
- B$[\mathrm{Xe}] 5 \mathrm{f}^4 7 \mathrm{~s}^2$
- C$[\mathrm{Xe}] 4 \mathrm{f}^6 6 \mathrm{~s}^2$
- D$[\mathrm{Xe}] 4 \mathrm{f}^1 5 \mathrm{~d}^1 6 \mathrm{~s}^2$
