- A$P$
- B$Na$
- ✓$F$
- D$I$
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${\text{C}}{{\text{l}}_2}\,{\text{(1}}\,{\text{atm) |}}\,{\text{C}}{{\text{l}}^ - }\,{\text{(1}}\,\,{\text{M)}}\,{\text{|| C}}{{\text{l}}^ - }\,(0.1\,M)\,|\,C{l_2}\,(2\,atm)$
$NO(g) + Br_2 (g) \rightleftharpoons NOBr_2 (g)$
$NOBr_2(g)+ NO(g) \longrightarrow 2NOBr(g)$
If the second step is the rate determining step, the order of the reaction with respect to $NO(g)$ is
Statement $(I)$ : The $\mathrm{NH}_2$ group in Aniline is ortho and para directing and a powerful activating group.
Statement $(II)$ : Aniline does not undergo FriedelCraft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :
