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JEE Main 24-Jan-2025 Paper - Shift 2 — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEEJEE Main 24-Jan-2025 Paper - Shift 24 Marks
MCQ
The elemental composition of a compound is $54.2 \%, C , 9.2 \% H$ and $36.6 \% O$. If the molar mass of the compound is $132 g mol ^{-1}$, the molecular formula of the compound is :
[Given : The relative atomic mass of $C : H : O =$ 12:1:16]
  • A
    $C _4 H _9 O _3$
  • B
    $C _6 H _{12} O _6$
  • ✓
    $C _6 H _{12} O _3$
  • D
    $C _4 H _8 O _2$
✓

Answer

Correct option: C.
$C _6 H _{12} O _3$
(C) $C _6 H _{12} O _3$
Sol.
Image
$C _2 H _4 O \Rightarrow$ Empirical formula
E.F. mass $=24+4+16=44$
and molar mass $=132$
Hence molecular formula $=\left( C _2 H _4 O \right)_3$
$\quad \quad\quad\quad\quad\quad\quad\quad\quad\quad
=C_6 H_{12} O_3
$
Correct Option (3)

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