The ends of a stretched wire of length $L$ are fixed at $x = 0$ and $x = L.$ In one experiment, the displacement of the wire is ${y_1} = A\sin (\pi x/L)\sin \omega t$ and energy is ${E_1}$, and in another experiment its displacement is ${y_2} = A\sin (2\pi x/L)\sin 2\omega t$ and energy is ${E_2}$. Then
  • A${E_2} = {E_1}$
  • B${E_2} = 2{E_1}$
  • C${E_2} = 4{E_1}$
  • D${E_2} = 16{E_1}$
IIT 2001, Medium
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