MCQ
The energy of an electron in ${n^{th}}$ orbit of hydrogen atom is
  • A
    $\frac{{13.6}}{{{n^4}}}\,eV$
  • B
    $\frac{{13.6}}{{{n^3}}}\,eV$
  • $\frac{{13.6}}{{{n^2}}}\,eV$
  • D
    $\frac{{13.6}}{n}\,eV$

Answer

Correct option: C.
$\frac{{13.6}}{{{n^2}}}\,eV$
c
It’s Obvious
 

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