MCQ
The energy of one mole of photons of radiation of frequency $2 \times 10^{12}\,Hz$ in $Jmol ^{-1}$ is $.....$(Nearest integer) (Given: $h =6.626 \times 10^{-34}\,JS$ $\left. N _{ A }=6.022 \times 10^{23}\, mol ^{-1}\right)$
  • A
    $796$
  • $798$
  • C
    $797$
  • D
    $785$

Answer

Correct option: B.
$798$
b
For one photon $E = hv$

For one mole photon,

$E=6 \cdot 023 \times 10^{23} \times 6.626 \times 10^{-34} \times 2 \times 10^{12}$

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