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5. Thermodynamics and thermochemistry — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry5. Thermodynamics and thermochemistry1 Mark
MCQ
Heat of neutralization of strong acid against strong base is constant and is equal to
  • A
    $13.7\, kcal$
  • B
    $57\, kJ$
  • C
    $5.7 \times {10^4}$ $J$
  • ✓
    All of the above
✓

Answer

Correct option: D.
All of the above
(d)$13.7\,\,kcal = 57\,kJ = 5.7 \times {10^4}\,J$.

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