The enthalpies of combustion of carbon and carbon monodie are -39… - Vidyadip

MCQ

The enthalpies of combustion of carbon and carbon monodie are $-393.5$ and $-283 \,kJ\, mol^{-1}$ respectivley. The enthalpy of formation of carbon monoxide per mole is.......$kJ$

A
$ - 676.5$
B
$676.5$
C
$110.5$
✓
$ - 110.5$

✓

Answer

Correct option: D.

$ - 110.5$

(d)$C(s) + {O_2}(g) \to C{O_2}(g)$
$\Delta H = - 393.5\,KJ\,mo{l^{ - 1}}$…..$(i)$
$CO(g) + 1/2{O_2}(g) \to C{O_2}(g)$
$\Delta H = - 283\,KJ\,mo{l^{ - 1}}$…..$(ii)$
On substracting equation $(ii)$ from equation $(i)$
We get
$C(s) + {O_2}(g) \to CO(g)$; $\Delta H = - 110.5\,KJ\,mo{l^{ - 1}}$
The enthalpy of formation of carbon monooxide per mole $ = - 110.5\,KJ\,mo{l^{ - 1}}$

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