MCQ
The equation ${(a + b)^2} = 4ab\,{\sin ^2}\theta $ is possible only when
  • A
    $2a = b$
  • $a = b$
  • C
    $a = 2b$
  • D
    None of these

Answer

Correct option: B.
$a = b$
b
(b) We have ${(a + b)^2} = 4ab{\sin ^2}\theta $

$ \Rightarrow {\sin ^2}\theta = \frac{{{{(a + b)}^2}}}{{4ab}} \le 1 $

$\Rightarrow {(a + b)^2} - 4ab \le 0$

$ \Rightarrow {(a - b)^2} \le 0 $

$\Rightarrow a = b.$

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