The equation $\left( {P + \frac{a}{{{V^2}}}} \right)$ $(V - b)$ constant. The units of $a$ are
A$Dyne \times c{m^5}$
B$Dyne \times c{m^4}$
C$Dyne/c{m^3}$
D$Dyne/c{m^2}$
Medium
Download our app for free and get started
B$Dyne \times c{m^4}$
b (b) Units of $a$ and $PV^2$ are same and equal to dyne $×$ $cm^4$.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Consider two physical quantities A and B related to each other as $E=\frac{B-x^2}{A t}$ where $E, x$ and $t$ have dimensions of energy, length and time respectively. The dimension of $A B$ is
The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $5.10 \ cm$ and $5.15 \ cm$ of the main scale. The vernier scale has $50$ division equivalent to $2.45 \ cm$. The $24^{\text {th }}$ division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is :
A student measures the thickness of a human hair by looking at it through a microscope of magnification $100$. He makes $20$ observations and finds that the average width of the hair in the field of view of the microscope is $3.5 \;mm$. What is the estimate on the thickness(in $mm$) of hair ?