The equation of a transverse wave is given by $y = 10\sin \pi (0.01x - 2t)$ where $x$ and $y$ are in $cm$ and $t$ is in second. Its frequency is .... ${\sec ^{ - 1}}$
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(c) Comparing with the standard equation,
$y = A\sin \frac{{2\pi }}{\lambda }(vt - x)$, we have
$v = 200$$cm/\sec $, $\lambda = 200$$cm\,;$$\therefore $$n = \frac{v}{\lambda } = 1$${\sec ^{ - 1}}$
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