The equation of a wave on a string of linear mass density $0.04\, kgm^{-1}$ is given by : $y = 0.02\,\left( m \right)\,\sin \,\left[ {2\pi \left( {\frac{t}{{0.04\left( s \right)}} - \frac{x}{{0.50\left( m \right)}}} \right)} \right]$. The tension in the string is ..... $N$
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$T = \mu {v^2} = \mu \frac{{{\omega ^2}}}{{{k^2}}} = 0.04\frac{{{{\left( {2\pi /0.004} \right)}^2}}}{{{{\left( {2\pi /0.50} \right)}^2}}} = 6.25\,N$
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