But $y=a \sin (\omega t-k x)$

$\therefore \omega=\frac{2 \pi}{0.04} \Rightarrow v=\frac{1}{0.04}=25 H z$

$k=\frac{2 \pi}{0.50} \Rightarrow \lambda=0.5 \mathrm{m}$

$\therefore$ velocity, $\mathrm{v}=v \lambda=25 \times 0.5 \mathrm{m} / \mathrm{s}=12.5 \mathrm{m} / \mathrm{s}$

Velocity on a string is given by

$v=\sqrt{\frac{T}{\mu}} \therefore T=\mathrm{v}^{2} \times \mu=(12.5)^{2} \times 0.04=6.25 \mathrm{N}$