The equation of the circle whose diameters have the end points (a… - Vidyadip

MCQ

The equation of the circle whose diameters have the end points $(a, 0), (0, b)$ is given by

✓
${x^2} + {y^2} - ax - by = 0$
B
${x^2} + {y^2} + ax - by = 0$
C
${x^2} + {y^2} - ax + by = 0$
D
${x^2} + {y^2} + ax + by = 0$

✓

Answer

Correct option: A.

${x^2} + {y^2} - ax - by = 0$

a
(a) Required equation is $(x - a)x + (y - b)y = 0$

or ${x^2} - ax + {y^2} - by = 0$.

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